已知实数x,y满足|2x+y+1|≤|x+2y+2|,且-1≤y≤1,则z=2x+y的最大值
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已知实数x,y满足|2x+y+1|≤|x+2y+2|,且-1≤y≤1,则z=2x+y的最大值
已知实数x,y满足|2x+y+1|≤|x+2y+2|,且-1≤y≤1,则z=2x+y的最大值
已知实数x,y满足|2x+y+1|≤|x+2y+2|,且-1≤y≤1,则z=2x+y的最大值
-1≤y≤1
0 ≤y+1≤2
设“y+1=k”
则 “0≤k≤2”
|2x+k|≤|x+2k|
则 (2x+k)*(2x+k)≤(x+2k)*(x+2k)
即 4x*x+4x*k+K*k≤x*x+4kx+4K*k
简化得 x*x≤k*k
所以 |x|≤|k|
0 ≤|k|≤2
则 |x| ≤2
-2 ≤ x ≤2
-4 ≤ 2x≤ 4
-1 ≤ y≤ 1
-5 ≤ 2x+y ≤ 5
z 的最大值就是 5
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