已知数列an满足an=a(n-1)/3a(n-1)+1,a1=1,则an=
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已知数列an满足an=a(n-1)/3a(n-1)+1,a1=1,则an=
已知数列an满足an=a(n-1)/3a(n-1)+1,a1=1,则an=
已知数列an满足an=a(n-1)/3a(n-1)+1,a1=1,则an=
1/an=[3a(n-1)+1]/a(n-1)=3+1/a(n-1)
1/a1=1
所以1/an=1+3(n-1)=3n-2
an=1/(3n-2)
取倒数,令an倒数为bn,得bn=b(n-1)+3.易得bn的通式为3n-2,则an的通式为1/(3n-2)
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