作业帮X趋于无穷大,求1/[x²sin²1/﹙3x﹚]的极限X趋于无穷大,求1/[x²sin²1/﹙3x﹚]的极限
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![X趋于无穷大,求1/[x²sin²1/﹙3x﹚]的极限X趋于无穷大,求1/[x²sin²1/﹙3x﹚]的极限](/uploads/image/z/7124951-47-1.jpg?t=X%E8%B6%8B%E4%BA%8E%E6%97%A0%E7%A9%B7%E5%A4%A7%2C%E6%B1%82%26%238203%3B1%2F%5Bx%26%23178%3Bsin%26%23178%3B1%2F%EF%B9%993x%EF%B9%9A%5D%E7%9A%84%E6%9E%81%E9%99%90X%E8%B6%8B%E4%BA%8E%E6%97%A0%E7%A9%B7%E5%A4%A7%2C%E6%B1%821%2F%5Bx%26%23178%3Bsin%26%23178%3B1%2F%EF%B9%993x%EF%B9%9A%5D%E7%9A%84%E6%9E%81%E9%99%90)
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X趋于无穷大,求1/[x²sin²1/﹙3x﹚]的极限X趋于无穷大,求1/[x²sin²1/﹙3x﹚]的极限
X趋于无穷大,求1/[x²sin²1/﹙3x﹚]的极限
X趋于无穷大,求1/[x²sin²1/﹙3x﹚]的极限
X趋于无穷大,求1/[x²sin²1/﹙3x﹚]的极限X趋于无穷大,求1/[x²sin²1/﹙3x﹚]的极限
令y=1/(3x),则原式=9*y*y/[sin(y)*sin(y)],在y趋于0极限下求值,利用罗比他法则求就行了