作业帮log9^3+log2^1/25×log3^1/8×5^1/9=
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/15 19:59:11
x)O3RFqF@@&Hev6Do=`BN~NvNH&cY8P%cIHjjki6
]c
1Ffgkh$ف U
log9^3+log2^1/25×log3^1/8×5^1/9=
log9^3+log2^1/25×log3^1/8×5^1/9=
log9^3+log2^1/25×log3^1/8×5^1/9=
原式
= lg3/lg9+lg(1/25)/lg2×lg(1/8)/lg3×lg(1/9)/lg5
= lg3/(2lg3)+(-2lg5)/lg2×(-3lg2)/lg3×(-2lg3)/lg5
= 0.5-12
= -11.5
log2(log9 3)的值
log9^3+log2^1/25×log3^1/8×5^1/9=
3^log9(25)+16^log4(2)-(根号7)^log7(9)+(-1)^log2(1)
log9(x-5)+log9(x=+3)=1 9是那个log的底
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)(log三次根号4 8)
log2^1/25×log3^8÷log9^5+(-1/2)^-2×(In兀)^0÷8^2/3
log4^27×log(8)25×log9^5
log4^27×log(8)25×log9^5
化简log2[log3(log5 125)]……1.化简log2[log3(log5 125)]2.5log2(log9 81)3.log9 4 +log3 8 /log1/3 164.求值(lg2)^2+两个2*lg5+lg503.log9 4 +log3 8除以log三分之一 16 4.求值(lg2)平方+lg2乘以lg5+lg50
化简:log2 2+log5 1-3^(2log9 5)+(3log3 5)^2+3^log3 2
log√3^9+log9^27+(1/4)log4^1/16
log√3^9+log9^27+(1/4)log4^1/16
计算:log2的3次方乘以log9的8次方
log2^3 x log9^5 x log25^8
关于log的计算log8（9）* log27 (32)log4 (3) *log9（2）- log 1/2（四倍根号下32）[log2(5)+log4(0.2)][log5(2)+log25(0.5)]小括号里的数字是真数,小括号外的数字是底数
log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(2log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(27)+log9(2)*log4(根27)
(log4^3+log8^3)*(log3^2+log9^2)-log2^4次√32(log4^3+log8^3)*(log3^2+log9^2)-log2^(4√32)（那个4是根号上的）（log旁边的数字是在最下面的）
(log4＾3+log8＾3)(log3＾2+log9＾2)+log2＾(32)的1/4次方