求1/(x+4)-1/(x+7)=1/(x+3)-1/(x+6)的值
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求1/(x+4)-1/(x+7)=1/(x+3)-1/(x+6)的值
求1/(x+4)-1/(x+7)=1/(x+3)-1/(x+6)的值
求1/(x+4)-1/(x+7)=1/(x+3)-1/(x+6)的值
1/(x+3)-1/(x+4)=1/(x+6)-1/(x+7)
(x+6)(x+7)=(x+3)(x+4)
6x=-30
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