已知(a-2)²+|b-1|=0,求代数式2a-3a²b+2ab²-a²b+3ab²-a的值.
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已知(a-2)²+|b-1|=0,求代数式2a-3a²b+2ab²-a²b+3ab²-a的值.
已知(a-2)²+|b-1|=0,求代数式2a-3a²b+2ab²-a²b+3ab²-a的值.
已知(a-2)²+|b-1|=0,求代数式2a-3a²b+2ab²-a²b+3ab²-a的值.
(a-2)²+|b-1|=0
那么a-2=0 b-1=0
a=2 b=1
2a-3a²b+2ab²-a²b+3ab²-a
=a-4a²b+5ab²
=2-4×4×1+5×2×1
=2-16+10
= -4
由已知(a-2)²+|b-1|=0得a=2,b=1,代数式化简为a-4a²b+5ab²,则把a=2,b=1代入计算得-4