求∫In[1/sin^4(x)]dx~不定积分啊~

求∫In[1/sin^4(x)]dx~不定积分啊~ 求∫1/(sin^4x+cos^4x)dx, ∫sin^4 (x) dx 求不定积分 In=∫1/sin^n(x)dx求不定积分的递推公式 ∫sinxcosx/(1+sin^4x)dx ∫1/sin^4x dx ∫sin(1/x)dx 求微积分 ∫sin^2(x)cos^4(x) dx 求∫1／tan^2x+sin^2x dx ∫1-sin2x/sin^2x-x dx求不定积分 求不定积分 ∫((1+sin^2x)/(1+cos2x))dx ∫sin（5-4x）dx求不定积分 求不定积分∫[1/(sin^2 cos^2(x)]dx 求不定积分∫sin(2x)/(1+cosx)dx ∫(1/sin²xcos²x)dx怎么求, 求不定积分∫[1/sin^2cos^2 (x)]dx 求不定积分：∫sin[x^(1/2)]dx 求积分的解∫（1/sin(x/2))dx