用因式分解法解下列方程:① (2x+3)^2=(5x-4)^2 ..② (x-根号下2)^2-2(根号下2-x)=0 ③ 4y^2+8y+4=0 ..④ (x-5)(x+3)+x(x+6)=-17 ..⑤ (3-x) ^2 =9-x ^2 ⑥(t-3)(t+4)=-12 ..⑦ (x+5)(x+3)+x(x+6)=-17 ..⑧x^2-2ax+a^2-b^2=0
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![用因式分解法解下列方程:① (2x+3)^2=(5x-4)^2 ..② (x-根号下2)^2-2(根号下2-x)=0 ③ 4y^2+8y+4=0 ..④ (x-5)(x+3)+x(x+6)=-17 ..⑤ (3-x) ^2 =9-x ^2 ⑥(t-3)(t+4)=-12 ..⑦ (x+5)(x+3)+x(x+6)=-17 ..⑧x^2-2ax+a^2-b^2=0](/uploads/image/z/959723-35-3.jpg?t=%E7%94%A8%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E6%B3%95%E8%A7%A3%E4%B8%8B%E5%88%97%E6%96%B9%E7%A8%8B%EF%BC%9A%E2%91%A0+%282x%2B3%29%5E2%3D%285x-4%29%5E2+..%E2%91%A1+%28x-%E6%A0%B9%E5%8F%B7%E4%B8%8B2%EF%BC%89%5E2-2%EF%BC%88%E6%A0%B9%E5%8F%B7%E4%B8%8B2-x%29%3D0+%E2%91%A2+4y%5E2%2B8y%2B4%3D0+..%E2%91%A3+%28x-5%29%28x%2B3%29%2Bx%28x%2B6%29%3D-17+..%E2%91%A4+%283-x%29+%5E2+%3D9-x+%5E2+%E2%91%A5%28t-3%29%28t%2B4%29%3D-12+..%E2%91%A6+%28x%2B5%29%28x%2B3%29%2Bx%28x%2B6%29%3D-17+..%E2%91%A7x%5E2-2ax%2Ba%5E2-b%5E2%3D0)
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