(3y-6)分之(2y+5)=(2y-4)分之(5y-4)+2分之1

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(3y-6)分之(2y+5)=(2y-4)分之(5y-4)+2分之1
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(3y-6)分之(2y+5)=(2y-4)分之(5y-4)+2分之1
(3y-6)分之(2y+5)=(2y-4)分之(5y-4)+2分之1

(3y-6)分之(2y+5)=(2y-4)分之(5y-4)+2分之1
2y+5/3y-6=5y-4/2y-4 + ½
2y+5/3y-6=2(5y-4)+2y-4/2(2y-4)
2y+5/3y-6=3y-3/y-2
(2y+5)×(y-2)=(3y-6)×(3y-3)
7y²-28y+28=0
(7y-14)(y-2)=0
y=2
2y-4=0
所以此题无实数解.