1/1x3+1/3x5 +1/(2n-1)(2n+2)=n/2n+1
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1/1x3+1/3x5 +1/(2n-1)(2n+2)=n/2n+1
1/1x3+1/3x5 +1/(2n-1)(2n+2)=n/2n+1
1/1x3+1/3x5 +1/(2n-1)(2n+2)=n/2n+1
1/1x3+1/3x5 +1/(2n-1)(2n+2)
=½[1-1/3+1/3-1/5+······+1/(2n-1)-1/(2n+1)]
=½(2n)/(2n+1)
=n/(2n+1)
因式分解:x5+x3+1
1x2+2x3+3x4+4x5+.+n(n+1)+n(n+2)=?
1x2+2x3+3x4+4x5.n(n+1)等于多少?急救!
1/1x3+1/3x5 +1/(2n-1)(2n+2)=n/2n+1
解一道方程组x1+x2+x3=5,x2+x3+x4=1,x3+x4+x5=-5,x4+x5+x1=-3,x5+x1+x2=2
1/1x3+1/2x4+1/3x5+
1x2+2x3+3x4+4x5+.+15x16
x1-x2+x3=1 x2-x3+x4=2 x3-x4+x5=3 x4-x5+x1=4 x5-x1+x2=5 求x1,x2,x3,x4,x5
等比数列中,求和:(2-3X5^-1)+(4-3X5^-2)+.(2n-3X5^-n)
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