lim(x^2+6x+5)/(x^2-3x-4)的极限,x趋于-1

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 18:07:14
lim(x^2+6x+5)/(x^2-3x-4)的极限,x趋于-1
x)}"H۬BN}W׸B}>ټƗ3'TdWMR>Y lȷ϶~ž}6O}1Ʀ$AMstMMYp

lim(x^2+6x+5)/(x^2-3x-4)的极限,x趋于-1
lim(x^2+6x+5)/(x^2-3x-4)的极限,x趋于-1

lim(x^2+6x+5)/(x^2-3x-4)的极限,x趋于-1
用洛必达法则求解

-4/5

用罗必达法则解 (见图)lim [(e^x)-1/sin(5x)]x->0lim [1-cos(5x)/1-cos(7x)]x->0lim x->0 [(8^x-7^x-1)/(x^2)-1]lim [1-(6/x)]^x x->∞ lim 7cos(3x)sec(9x)x->pi/2 数学难题,求指教~~极限到底是什么玩意我还不懂.1.lim(x^2-2x+6)2.lim(x^2-4)/(x-2)3.lim(x^2-6x=8)/(x^-5x=4)4.lim[1/(1-x)-1/(1-x^3)5.lim(sin2x)/x^26.lim(sin5x)/x7.lim(tan3x)/(sin7x)8.lim[(1+x)/x]^2x例如这道例题~lim[(1/3)x+1] 1、lim(x->无穷大) e^x arctanx2、lim(x->0)sinx√1+sin(1/x)3、lim(x->无穷大)【(√x^2+x+1)-【(√x^2-x+1)】4、lim(x->无穷大)((x+{x+(x)^0.5]^0.5}^0.5)/(2x+1)^0.55、lim(x->0)(sin3x+x^2sin1/x)/((1+cosx)x)6、lim(n->无穷大)(2^n)(si 求极限 lim(x->3)(x+1)/(x^2-5x+6) lim(x趋于-2)x^2-x-6/x^2+3x+2 lim(x^2+2x-5)/(x^3+x+5),x趋于无穷 lim(x趋向于4)(x^2-6x+8)/(x^2-5x+4) 1.lim x->∞ (2x/x^2+1)*cosx 2..lim x->∞{ [(x^2-x)arctanx]/x^3-x-5}3..lim x->0 (e^x-e^-x-2x)/(x-sinx) 4..lim x->0 (sinx-x)/(x^3) 5..lim x->0 (x^2*tanx)/(x-tanx) 6..lim x->0 (1+3/x)^2x 7..lim x->0 (1+2x)^(3/sinx) 8.lim x->∞ (x/1+x)^(x-3) 9..li lim(x^2+6x+5)/(x^2-3x-4)的极限,x趋于-1 lim(x→0) (3x^2-5x+2), lim(2x-3/2x+1)^x+1 烦人的数学微积分1、lim(x→0)Sin3x/Sin2x2、lim(x→0)x/3*Sin3x3、lim(x→0)[Xsin(3/x)+(tanx/2x)]4、lim(x→3)Sin(x-3)/(X^2-X-6)5、lim(x→∞)[1+(1/2x)^x6、lim(x→∞)(x+3/x)^x7、lim(x→0)(1-x/2)^1/x+118、求下列函数的间断 用洛必达法则求几个极限(有图)~用洛必达法则求以下极限(见图)lim [(e^x)-1/sin(5x)]x->0lim [1-cos(5x)/1-cos(7x)]x->0lim x->0 [(8^x-7^x-1)/(x^2)-1]lim [1-(6/x)]^x x->0 lim 7cos(3x)sec(9x)x->∞(搞错了~应该是>/ 求lim(4x^2-3x)/-5x^2+2x-6 lim(2-x)^3(3+x)^5/(6-x)^8 x趋近于无穷 lim(3x^2*sin2/x)/(5x+3),x—>0 求极限lim [(2x+6)sin(5/x)]/(4x+3) x+∞ lim(x→∞)[(3+x)/(6+x)]的[(x-1)/2]次方的极限