已知sin(π/6-α)=1/4,则sin(π/6+2α)=(),
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已知sin(π/6-α)=1/4,则sin(π/6+2α)=(),
已知sin(π/6-α)=1/4,则sin(π/6+2α)=(),
已知sin(π/6-α)=1/4,则sin(π/6+2α)=(),
sin(π/6-α)=1/4,
则cos(π/3-2α)=cos[2(π/6-α)]
=1-2 sin²(π/6-α)
=7/8.
所以cos(2α-π/3) =7/8.
sin(π/6+2α)= sin((2α-π/3)+ π/2)
= cos(2α-π/3)==7/8.
sin(π/6-α)=1/4,cos(π/6-α)=根号15/4或cos(π/6-α)=-根号15/4
sin2(π/6-α)=2sin(π/6-α)cos(π/6-α)=根号15/8或-根号15/8
cos2(π/6-α)=7/8或-7/8
因此sin(π/6+2α)=sin[π/2-2(π/6-α)]=cos2(π/6-α)=7/8或-7/8
sin(π/6+2α)=7/8
因为sin(π/6-α)=1/4,则cos(π/6-α)=√15/4
所以sin2(π/6-α)=√15/8=sin2(π/3-α)
拆开:sin90°cos(30°+2α)+cos90°sin(30°+2α)=√15/8
所以cos(30°+2α)=√15/8
所以sin(30°+2α)=7/8
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