y2=1/sqrt(x2)+x2-2;图像怎么画matlab

y2=1/sqrt(x2)+x2-2;图像怎么画matlab matlab画出雪花曲线function y=koch(x1,x2,y1,y2,n)if n>1koch(x1,y1,(2*x1+x2)/3,(2*y1+y2)/3,n-1);koch((2*x1+x2)/3,(2*y1+y2)/3,(x1+x2)/2+(y1-...y2)*sqrt(3)/6,(y1+y2)/2+(x2-x1)*sqrt(3)/6,n-1);koch((x1+x2)/2+(y1-y2)*sqrt(3)/6,(y1+y2)/2+(x2-...x1)*sqr f6 ={0.5-[sin(sqrt(x2+y2)2-0.5]}/(1+0.001*(x2+y2))2这个函数的极值值是多少啊 怎样用matlab解方程组?x1+x01=sqrt(x2^2+y2^2)*cos(a+atan(y2/x2))+qrt(x01^2+y01^2)*cos(a+atan(y01/x01))；y1+y01=sqrt(x2^2+y2^2)*sin(a+atan(y2/x2))+y02=sqrt(x01^2+y01^2)*sin(a+atan(y01/x01))其中x1,y1,x2,y2是已知量,要求x01,y01. 杭电2001.为什么是wrong answer?#include#includemain(){float x1,x2,y1,y2;while(scanf(%f %f %f %f,&x1,&x2,&y1,&y2)!=EOF){printf(%.2f,sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)));putchar(' ');}} y=x+√(1-x2) y2=x2+(1-x2)+2x√(1-x2) 若(x2+y2)(1-x2-y2)+6=0,则x2+y2=?带过程（注2是平方） 若(x2+y2)四次方-2(x2+y2)2+1=0,求x2+y2的值 已知实数x.y满足（x2+y2）（x2+y2-1）=2,求x2+y2的值 已知x,y满足（x2+y2）(x2+y2-1)=2,则x2+y2的值为多少?x2,y2表示x和y的平方 (x2-2xy+y2)-(x2+2xy+y2)=什么 （x2+y2）2-（x2+y2）-6= x2-y2=1图像 已知x.y为实数且x2+y2+12≤xy+6y,则sqrt{x+2y-1}= 结果为3,请提供过程, （x2+y2）2-y2=x2+6 则x2+Y2=? 详细! （x2+y2）2-y2=x2+6 则x2+Y2=? 若X2+xy-2y2=0,则（x2+3xy+y2)/x2+y2=? 已知:(x2+y2-3)(2x2+2y2-4)=24,求x2+y2的值