求y=sin(2x+π/3)+cos(2x-π/6)的单调区间

y =(cos^2) x - sin (3^x),求y' Sin x-sin y=2/3 cos x-cos y=1/2 求cos(x-y) 已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos（x+y）+cos（x-y）】的值 sin(x+y)sin(x-y)=k,求cos^2x-cos^2y 当cos^2x-cos^2y=√3/2时,求sin(x+y）×sin(x-y) 求y=sin＾2(x)+3sin(x)cos(x)-2cos＾2(x)的最大值 求y=sin x +2sin x cos x -3cos²x 的周期和值域, 已知Sin x+Sin y=1/2,Cos x+Cos y=根号3/3,求S求Sin(x-y)/2 问道三角函数题已知sin(x)-sin(y)=-(2/3);cos(x)-cos(y)=(2/3);求cos(x-y) sin^2x+cos^2y=1/2 求3sin^2x+sin^2y的最值 求y=sin(2x+π/3)+cos(2x-π/6)的单调区间 y=sin(π/3-2x)+cos(2x)的周期怎么求? 求函数y=cos(9/2π+x)+sin^2x的最大值和最小值还有一题 已知sinx+cosx=1/2,求sin^3x+cos^3x和sin^4x+cos^2x 求y=sin x/(2-cos x)值域 已知sin(x)+3cos(x)=2,求sin(x)-cos(x)/sin(x)+cos(x)=? 化简y=sin^2(x)+2sin(x)cos(x)+3cos^2(x) y=(sin x + COS x)^2 2sin^2x - 5sin x cos x=3 cos^2x,求X,