作业帮高数积分题,具体过程!nlim sin(π/n) ∑ [1/(1 + Cos[k/n])]n->无穷大 k=1n在∑上面，k=1在∑下面
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![高数积分题,具体过程!nlim sin(π/n) ∑ [1/(1 + Cos[k/n])]n->无穷大 k=1n在∑上面，k=1在∑下面](/uploads/image/z/1831702-22-2.jpg?t=%E9%AB%98%E6%95%B0%E7%A7%AF%E5%88%86%E9%A2%98%2C%E5%85%B7%E4%BD%93%E8%BF%87%E7%A8%8B%21nlim+++sin%28%CF%80%2Fn%29+%E2%88%91+%5B1%2F%281+%2B+Cos%5Bk%2Fn%5D%29%5Dn-%3E%E6%97%A0%E7%A9%B7%E5%A4%A7++++++k%3D1n%E5%9C%A8%E2%88%91%E4%B8%8A%E9%9D%A2%EF%BC%8Ck%3D1%E5%9C%A8%E2%88%91%E4%B8%8B%E9%9D%A2)
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高数积分题,具体过程!nlim sin(π/n) ∑ [1/(1 + Cos[k/n])]n->无穷大 k=1n在∑上面，k=1在∑下面
高数积分题,具体过程!
n
lim sin(π/n) ∑ [1/(1 + Cos[k/n])]
n->无穷大 k=1
n在∑上面，k=1在∑下面
高数积分题,具体过程!nlim sin(π/n) ∑ [1/(1 + Cos[k/n])]n->无穷大 k=1n在∑上面，k=1在∑下面
=sin(π/n)/ (π/n)lim π/n ∑ [1/(1 + Cos[k/n])]
=lim π/n ∑ [1/(1 + Cos[k/n])]
=πlim 1/n ∑ [1/(1 + Cos[k/n])]
=π积分号[1/(1 + Cosx)]dx(x从0到1）
下面的过程就不详述了.