∫sin(3x)cos(4x)dx=

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∫sin(3x)cos(4x)dx=
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∫sin(3x)cos(4x)dx=
∫sin(3x)cos(4x)dx=

∫sin(3x)cos(4x)dx=
∫sin(3x)cos(4x)dx
=1/2∫[sin(3x+4x)+sin(3x-4x)]dx
=1/2∫[sin(7x)+sin(-x)]dx
=-1/14cos7x+1/2sinx+C

用积化和差公式
原式=1/2∫(sin7x-sinx)dx
=-1/14*cos7x+1/2*cosx+C

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