作业帮log2 SQR(7/48)+log2 12 -1/2log2 42
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log2 SQR(7/48)+log2 12 -1/2log2 42
log2 SQR(7/48)+log2 12 -1/2log2 42
log2 SQR(7/48)+log2 12 -1/2log2 42
log2√(7/48)+log2 12 -1/2log2 42
=log2√(7/48)+log2(12)-log2√42
=log2√(7/48)*12/√42
=log2√7*144/48*42
=log2√(1/2)
=1/2log2(1/2)
=-1/2
log2 SQR(7/48)+log2 12 -1/2log2 48
log2 SQR(7/48)+log2 12 -1/2log2 42
log2[√(7/48)]+log2(12)-log2(√42)
log2(log2
1/2log2(7/48)+log2 12-1/2log2 42log2 的2 在g的右下脚
化简算式log2^√7/48+log2^12-1/2log2^42+1/2^log2^3
log2(根号下7/48)+log2(12)-1/2log2(42)-1=?
log2根号7/48+log2^12-1/2log2^42-1=
求化简log2根号下48分之7+log2 12-log2 42
求值：log2√(7/48)+log2(12)-1/2log2(42)-1 这道题我算来算去算不对
计算log2 √(48/7)-log2 12+(1/2)log2 42-1
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