100分求一道数学题,After t years the population of a certain town is P(t) = 50+5t thousand people.A populationP has an associated CO2 level,C(P) = (根号下(P2 + 1))/2.After 2 years,the rate at which CO2 level is changing with respect to t

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/06 00:21:39
100分求一道数学题,After t years the population of a certain town is P(t) = 50+5t thousand people.A populationP has an associated CO2 level,C(P) = (根号下(P2 + 1))/2.After 2 years,the rate at which CO2 level is changing with respect to t
xTNQF[ ߈&C;&̤sV.ЋR@. XB[1Ιi 1X($=묳SG8EpN:yPo:I"ESIj@B:IXARa2#CXE^%XLkURԈ) $j jD ")28,]m&u8xG٠,  T@H̄IJTMDog`$ 鮹b$'2 Ѓt)Z(e̵^k1t[e:fyoT̽KZ?2V>F. V4CZÞa3qp4[˫f&q|ܦ;#,,q^048߅yĐZunkӮ<1pX7^R˄ /M/?/3, Y#6i^_B+BAz~E) Mc#_csJ/s:nsOV)R]c?

100分求一道数学题,After t years the population of a certain town is P(t) = 50+5t thousand people.A populationP has an associated CO2 level,C(P) = (根号下(P2 + 1))/2.After 2 years,the rate at which CO2 level is changing with respect to t
100分求一道数学题,
After t years the population of a certain town is P(t) = 50+5t thousand people.A populationP has an associated CO2 level,C(P) = (根号下(P2 + 1))/2.After 2 years,the rate at which CO2 level is changing with respect to t will be:答案是150/根号下3601 实在闹不明白为什么,
C(P) = (根号下(P2 + 1))/2.P后面的2表示P的平方

100分求一道数学题,After t years the population of a certain town is P(t) = 50+5t thousand people.A populationP has an associated CO2 level,C(P) = (根号下(P2 + 1))/2.After 2 years,the rate at which CO2 level is changing with respect to t
P(t)=50+5t
C(p)=(根号下(P2 + 1))/2.
求的是变化率
C(p)=[根号下(50+5t)²+1]/2=[根号下(2501+500t+25t²)]/2
dC/dt=(500+50t)/{4[根号下(2501+500t+25t²)]}
当t=2的时候
dC/dt=(500+100)/[4根号下(3601)]
=600/[4根号下(3601)]
=150/[根号下(3601)]

123

题目的意思是:T年之后某个小镇的人数是P(t)=50+5t(千人)。人数p和CO2的含量有关,具体关系是C(p)=(根号下(P2 + 1))/2.
2年后CO2将会是多少?还有你的答案是多少啊,,你打的是这个答案吗?150/根号下3601恩,求解你的答案是150/根号下3601 360后面有1吗?算了,不会了。。。有,你看题目就知道了,根号下P^2+1 前面公式求出进去就是...

全部展开

题目的意思是:T年之后某个小镇的人数是P(t)=50+5t(千人)。人数p和CO2的含量有关,具体关系是C(p)=(根号下(P2 + 1))/2.
2年后CO2将会是多少?还有你的答案是多少啊,,你打的是这个答案吗?150/根号下3601

收起