100分求一道数学题,After t years the population of a certain town is P(t) = 50+5t thousand people.A populationP has an associated CO2 level,C(P) = (根号下(P2 + 1))/2.After 2 years,the rate at which CO2 level is changing with respect to t

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100分求一道数学题,After t years the population of a certain town is P(t) = 50+5t thousand people.A populationP has an associated CO2 level,C(P) = (根号下(P2 + 1))/2.After 2 years,the rate at which CO2 level is changing with respect to t
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100分求一道数学题,After t years the population of a certain town is P(t) = 50+5t thousand people.A populationP has an associated CO2 level,C(P) = (根号下(P2 + 1))/2.After 2 years,the rate at which CO2 level is changing with respect to t
100分求一道数学题,
After t years the population of a certain town is P(t) = 50+5t thousand people.A populationP has an associated CO2 level,C(P) = (根号下(P2 + 1))/2.After 2 years,the rate at which CO2 level is changing with respect to t will be:答案是150/根号下3601 实在闹不明白为什么,
C(P) = (根号下(P2 + 1))/2.P后面的2表示P的平方

100分求一道数学题,After t years the population of a certain town is P(t) = 50+5t thousand people.A populationP has an associated CO2 level,C(P) = (根号下(P2 + 1))/2.After 2 years,the rate at which CO2 level is changing with respect to t
P(t)=50+5t
C(p)=(根号下(P2 + 1))/2.
求的是变化率
C(p)=[根号下(50+5t)²+1]/2=[根号下(2501+500t+25t²)]/2
dC/dt=(500+50t)/{4[根号下(2501+500t+25t²)]}
当t=2的时候
dC/dt=(500+100)/[4根号下(3601)]
=600/[4根号下(3601)]
=150/[根号下(3601)]

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题目的意思是:T年之后某个小镇的人数是P(t)=50+5t(千人)。人数p和CO2的含量有关,具体关系是C(p)=(根号下(P2 + 1))/2.
2年后CO2将会是多少?还有你的答案是多少啊,,你打的是这个答案吗?150/根号下3601恩,求解你的答案是150/根号下3601 360后面有1吗?算了,不会了。。。有,你看题目就知道了,根号下P^2+1 前面公式求出进去就是...

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题目的意思是:T年之后某个小镇的人数是P(t)=50+5t(千人)。人数p和CO2的含量有关,具体关系是C(p)=(根号下(P2 + 1))/2.
2年后CO2将会是多少?还有你的答案是多少啊,,你打的是这个答案吗?150/根号下3601

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