已知数列{an}满足a1=31,a(n)=a(n-1)-2(n大于等于2,n属于自然数)设bn=|an|,求数列{an}的前n项和Tn
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/13 04:25:52
x){}KMczub^_lۜhhkl~OG=`!kb>]ɮk;NӍlTbݾ<ۚļg?7O'$lC(`EF!cd.n_1_i '$1]#
FMX~qAb
已知数列{an}满足a1=31,a(n)=a(n-1)-2(n大于等于2,n属于自然数)设bn=|an|,求数列{an}的前n项和Tn
已知数列{an}满足a1=31,a(n)=a(n-1)-2(n大于等于2,n属于自然数)设bn=|an|,求数列{an}的前n项和Tn
已知数列{an}满足a1=31,a(n)=a(n-1)-2(n大于等于2,n属于自然数)设bn=|an|,求数列{an}的前n项和Tn
a(n)=a(n-1)-2
a(n)-a(n-1)=-2
{an}为等差数列,公差d=-2
an=31-2(n-1)=-2n+33
已知数列{an}满足a1=33,a(n+1)-an=2n,求an/n的最小值
已知数列an满足a1=2,an=a(n-1)+2n,(n≥2),求an
已知数列{an}满足a1=1,a(n+1)=nan n+1是角标
已知数列{an}满足a1=2,a(n+1)-an=a(n+1)*an,则a31=?
已知数列{an}满足a(n+1)=an+n,a1=1,则an=
已知数列{a}满足a1=1/2,a(n+1)=an+1/(n^2+n),求an已知数列{a}满足a1=1/2,a(n+1)=an+1/(n^2+n),求an
已知数列an满足条件a1=-2 a(n+1)=2an/(1-an) 则an=
已知数列{an}满足a(n+1)=an+lg2,a1=1,求an
已知数列{An}满足a1=1,a(n+1)=2an+1 求证数列{an+1}是等比数列 求数列{an}通式
已知数列{an}满足a1=1,a(n+1)=sn+(n+1)求:an和sn
已知数列{an}满足:a1=1,且an-a(n-1)=2n.求a2,a3,a4.求数列{an}通项an
已知数列{an}满足:a1=1,an=a1+2a2+3a3+``````+(n-1)a(n-1)(n大于等于2),则通项公式an是什么?
已知数列{an}满足a1=2,a(n+1)=1+an/1-an(n∈N*),a1*a2*a3*...*a2010的值为
已知数列{an}满足a1=1,a(n+1)=2an+1.求证(1)数列a(n+1)是等比数列;(2)求an
1)已知数列{An}满足:An+2/A(n-1)=3 (n大于等于2) A1=32)已知数列{An}满足:A1=1/2,AnA(n+1)=An-A(n+1)3)已知数列{An}满足:A1=1,A(n+1)=2An+3第一小题没看懂诶 下标的 和别的加一减一搞不清楚了
已知数列{an}满足a1=31,a(n)=a(n-1)-2(n大于等于2,n属于自然数)设bn=|an|,求数列{an}的前n项和Tn
已知数列{an}满足a1=1,3a(n+1)+an-7
一到数列题已知数列an满足a1=1 a(n+1)=an+(2n+3),求通项公式an