作业帮matlab中为什么这个函数只能输出第一个参数?function [n,y]=HT(f,c,e)%计算步长y1=diff(f,2);f1=@(x)eval(y1);,fmin]=fminbnd(f1,c(1),c(2));y1=diff(-f,2);f1=@(x)eval(y1);,fmax]=fminbnd(f1,c(1),c(2));b=max(abs(fmin),abs(fmax));n=ceil((b*(
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![matlab中为什么这个函数只能输出第一个参数?function [n,y]=HT(f,c,e)%计算步长y1=diff(f,2);f1=@(x)eval(y1);,fmin]=fminbnd(f1,c(1),c(2));y1=diff(-f,2);f1=@(x)eval(y1);,fmax]=fminbnd(f1,c(1),c(2));b=max(abs(fmin),abs(fmax));n=ceil((b*(](/uploads/image/z/2730459-3-9.jpg?t=matlab%E4%B8%AD%E4%B8%BA%E4%BB%80%E4%B9%88%E8%BF%99%E4%B8%AA%E5%87%BD%E6%95%B0%E5%8F%AA%E8%83%BD%E8%BE%93%E5%87%BA%E7%AC%AC%E4%B8%80%E4%B8%AA%E5%8F%82%E6%95%B0%3Ffunction+%5Bn%2Cy%5D%3DHT%28f%2Cc%2Ce%29%25%E8%AE%A1%E7%AE%97%E6%AD%A5%E9%95%BFy1%3Ddiff%28f%2C2%29%3Bf1%3D%40%28x%29eval%28y1%29%3B%2Cfmin%5D%3Dfminbnd%28f1%2Cc%281%29%2Cc%282%29%29%3By1%3Ddiff%28-f%2C2%29%3Bf1%3D%40%28x%29eval%28y1%29%3B%2Cfmax%5D%3Dfminbnd%28f1%2Cc%281%29%2Cc%282%29%29%3Bb%3Dmax%28abs%28fmin%29%2Cabs%28fmax%29%29%3Bn%3Dceil%28%28b%2A%28)
matlab中为什么这个函数只能输出第一个参数?function [n,y]=HT(f,c,e)%计算步长y1=diff(f,2);f1=@(x)eval(y1);,fmin]=fminbnd(f1,c(1),c(2));y1=diff(-f,2);f1=@(x)eval(y1);,fmax]=fminbnd(f1,c(1),c(2));b=max(abs(fmin),abs(fmax));n=ceil((b*(
matlab中为什么这个函数只能输出第一个参数?
function [n,y]=HT(f,c,e)
%计算步长
y1=diff(f,2);
f1=@(x)eval(y1);
,fmin]=fminbnd(f1,c(1),c(2));
y1=diff(-f,2);
f1=@(x)eval(y1);
,fmax]=fminbnd(f1,c(1),c(2));
b=max(abs(fmin),abs(fmax));
n=ceil((b*(c(2)-c(1))^3/12/e)^0.5);
%进行计算
h=(c(2)-c(1))/n;
i=1:n+1;
x(i)=c(1)+(i-1)*h;
y=subs(f,c(1))+subs(f,c(2));
for i=2:n-1
y=y+2*subs(f,x(i));
end
y=h/2*y;
把y放前面只输出y，n放前面只输出n。为什么会这样呢…………？
matlab中为什么这个函数只能输出第一个参数?function [n,y]=HT(f,c,e)%计算步长y1=diff(f,2);f1=@(x)eval(y1);,fmin]=fminbnd(f1,c(1),c(2));y1=diff(-f,2);f1=@(x)eval(y1);,fmax]=fminbnd(f1,c(1),c(2));b=max(abs(fmin),abs(fmax));n=ceil((b*(
是不是你调用的时候有问题?按照你的意思,调用应该如此：
[a,b]=HT(f,c,e)
其中a存放n的结果,b存放y的结果.
f、c、e则应该输入实际的参数.