几道高1数学题~求详解!谢谢!3Q!1.设向量a=(cos(x+y),sin(x+y)),向量b=(cos(x-y),sin(x-y),且a+b=(0.8,0.6)求(1).tana 2.已知f(x)=√3 sinax+cos(ax+π/3)+cos(ax-π/3)其中a大于0(1)求函数值域 (2)若函数最小正周期

来源:学生作业帮助网 编辑:作业帮 时间:2024/09/21 13:40:36
几道高1数学题~求详解!谢谢!3Q!1.设向量a=(cos(x+y),sin(x+y)),向量b=(cos(x-y),sin(x-y),且a+b=(0.8,0.6)求(1).tana 2.已知f(x)=√3 sinax+cos(ax+π/3)+cos(ax-π/3)其中a大于0(1)求函数值域  (2)若函数最小正周期
xTN@~p6B=HySRQB$@!"J@m A0>@y6ΉW̮%\R6ffvMB>X|ZlAz7Q:: 9O,3:Pⳗsͫ܋,ߨθ Fi32)sf(j^6k|{Wu1Ϗ|Q2=8lZ )@H(5)lZzU7s/9allwTJ'dU.u]}xT.x6'X(u,8cٍ,i&-AuQ#fWE l{ΆE#-,T ,S2;*F-6ͼQVFd@3:e g{(/@''c ueK%5J'êg JWN:L2cE갻*LIqڨBiN ;yM"D(X d>1$tm飺J4VuEcmC77,9 ;I N7u1ɇLGhp0bц-)a.ɋK{Jj~x [Rx1 xV>ݵ0Gpu Pn3־{˦is9/;I'D

几道高1数学题~求详解!谢谢!3Q!1.设向量a=(cos(x+y),sin(x+y)),向量b=(cos(x-y),sin(x-y),且a+b=(0.8,0.6)求(1).tana 2.已知f(x)=√3 sinax+cos(ax+π/3)+cos(ax-π/3)其中a大于0(1)求函数值域 (2)若函数最小正周期
几道高1数学题~求详解!谢谢!3Q!
1.设向量a=(cos(x+y),sin(x+y)),向量b=(cos(x-y),sin(x-y),且a+b=(0.8,0.6)求(1).tana
2.已知f(x)=√3 sinax+cos(ax+π/3)+cos(ax-π/3)其中a大于0
(1)求函数值域 (2)若函数最小正周期为π/2,则当x∈[0,π/2]时,函数的单调增区间
3.已知向量m=(sinA,cosA),向量n=(√3,-1),且m×n=1,且A为锐角
求(1)角A的大小
(2)函数f(x)=cos2x+4cosAsinx的值域
求详解!谢谢!能答几题算几题,谢谢!答得好加分!谢谢!
谢谢各位!
第1题求tanx(不好意思)
第2第3是根号3

几道高1数学题~求详解!谢谢!3Q!1.设向量a=(cos(x+y),sin(x+y)),向量b=(cos(x-y),sin(x-y),且a+b=(0.8,0.6)求(1).tana 2.已知f(x)=√3 sinax+cos(ax+π/3)+cos(ax-π/3)其中a大于0(1)求函数值域 (2)若函数最小正周期
1.向量a加上向量b=[cos(x+y)+cos(x-y),sin(x+y)+sin(x-y)]
=(cosxcosy-sinxsiny+cosxcosy+sinxsiny,sinxcosy+cosxsiny+sinxcosy-cosxsiny)
=(2cosxcosy,2sinxcosy)=(0.8,0.6)
所以2cosxcosy=0.8 推出cosxcosy=0.4
2sinxcosy=0.6 推出sinxcosy=0.3
sinxcosy/cosxcosy=tanx=3/4
2.f(x)=根3sinax+cos(ax+π/3)+cos(ax-π/3)
=根3sinax+cosaxcosπ/3-sinaxsinπ/3+cosaxcosπ/3+sinaxsinπ/3
=根3sinax+2cosaxcosπ/3=根3sinax+cosax=2sin(ax+π/6)
(1)所以f(x)的值域为[-2,2]
(2)a=2π/(π/2)=4 剩下你自己做吧.累死了...