y=(2x^2-3x+4)/√ x 求y' y=(2x^2-3x+4)除以根号X 求 y'
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y=(2x^2-3x+4)/√ x 求y' y=(2x^2-3x+4)除以根号X 求 y'
y=(2x^2-3x+4)/√ x 求y' y=(2x^2-3x+4)除以根号X 求 y'
y=(2x^2-3x+4)/√ x 求y' y=(2x^2-3x+4)除以根号X 求 y'
化简得Y=2X^(3/2)—3X^(1/2)+4X^(-1/2)
因为Y=X^n,求导y'=nX^(n-1)
所以各项求导得y'=3X^(1/2)— 1.5*X^(-1/2)—2X^(-3/2)
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