若x^2+2x+y^2-6y+10=0,则x-y
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若x^2+2x+y^2-6y+10=0,则x-y
若x^2+2x+y^2-6y+10=0,则x-y
若x^2+2x+y^2-6y+10=0,则x-y
x^2+2x+y^2-6y+10=0
(x+1)^2 + (y-3)^2 = 0
x = -1,y = 3
x-y = -1 -3 = -4
若x^2+y^2-10x-6y+34=0,求(x-y)/(x+y)的值
若x^2+2x+y^2-6y+10=0,则x-y
若x^2+y^2-10x+6y+34=0,则x+y=?
若x²+2x+y²-6y+10=0求x y
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已知x^2+y^2--6x--2y+10=0,求x+y/x--y
已知x^2+y^2+6x-2y+10=0,求x+y/x-y的值谢谢