已知cos(a+b)=0.2 ,cos(a-b)=0.6 求tana*tanb已知cos(a+b)=0.2 ,cos(a-b)=0.6求tana*tanb
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已知cos(a+b)=0.2 ,cos(a-b)=0.6 求tana*tanb已知cos(a+b)=0.2 ,cos(a-b)=0.6求tana*tanb
已知cos(a+b)=0.2 ,cos(a-b)=0.6 求tana*tanb
已知cos(a+b)=0.2 ,cos(a-b)=0.6
求tana*tanb
已知cos(a+b)=0.2 ,cos(a-b)=0.6 求tana*tanb已知cos(a+b)=0.2 ,cos(a-b)=0.6求tana*tanb
由cos(a+b)=0.2 得 cosacosb-sinasinb=0.2 ①
由cos(a-b)=0.6 得 cosacosb+sinasinb=0.6 ②
①+②得 2cosacosb=0.8,即cosacosb=0.4
②-①得 2sinasinb=0.4,即sinasinb=0.2
②÷①可得 tanatanb=sinasinb/cosacosb=0.2/0.4=0.5
cos(a+b)=0.2 ,cos(a-b)=0.6
∴cosacosb-sinasinb=0.2 ①
cosacosb+sinasinb=0.6 ②
①+②得2cosacosb=0.8,cosacosb=0.4
②-①得2sinasinb=0.4,sinasinb=0.2
∴tanatanb=sinasinb/cosacosb=0.2/0.4=0.5
0.5
cos(a+b)=cosacosb-sinasinb=0.2````````1式
cos(a-b)=cosacosb+sinasinb=0.6````````2式
1式加2式等于cosacosb=0.4
1式减2式等于sinasinb=0.2
tana*tanb =0.2/0.4=0.5
给分吧!
已知: cos(A+B)=0.2,cos(A-B)=0.6.
求:tanAtanB.
∵cos(A+B)=0.2,cos(A-B)=0.6
将两式展开
cosAcosB-sinAsinB=0.2…①
cosAcosB+sinAsinB=0.6…②
联立两式可得sinAsinB=0.2,cosAcosB=0.4
∴tanAtanB=(sinAsinB)/( cosAcosB)=0.5.