求不定积分,∫xtanx^2dx

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求不定积分,∫xtanx^2dx
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求不定积分,∫xtanx^2dx
求不定积分,∫xtanx^2dx

求不定积分,∫xtanx^2dx
不清楚你的平方是放在哪的?

解;
∫x(tanx)^2dx
=∫x[(secx)^2-1]dx
=∫x (secx)^2 dx-∫x dx
=∫x d(tanx) -x^2/2(下面用分步积分法)
=xtanx-∫tanxdx -x^2/2
=xtanx+ln|cosx|-x^2/2+C
(C常数)可以再详细点吗?有些地方写得不清楚

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