因式分解:X四次方+16,注意,是+16

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/16 02:38:12
因式分解:X四次方+16,注意,是+16
xTN@H<܈Z/eD?`eJכ@^D$@ZAҖ_x/&F ]va9g=3B> &( :ka,N:P['{ʼn|VxelKots23fALcm]ᠠ>&2I >Bb?)) ~.{>xC,$/U1(7SjȄb>@XYV"c; o/q{V"֑T8 g7oT6;'VqbƤI{7X 4HS:-N`;0n0I1(3~27 p'{DǺ[;JvHzƸM ɸ%Vt| 2[]j]UϖUe/K?vc)?@

因式分解:X四次方+16,注意,是+16
因式分解:X四次方+16,注意,是+16

因式分解:X四次方+16,注意,是+16
解原式=x^4+8x^2+16-8x^2
=(x^2+4)^2-(2倍根号2*x)^2
=(x^2+2倍根号2*x+4)(x^2-2倍根号2*x+40

x^4+16
=(x²)²+4²
=(x²)²+8x²+4²-8x²
=(x²+4)²-8x²
=(x²+4)²-(2√2x)²
=(x²+4+2√2x)(x²+4-2√2x)
=(x...

全部展开

x^4+16
=(x²)²+4²
=(x²)²+8x²+4²-8x²
=(x²+4)²-8x²
=(x²+4)²-(2√2x)²
=(x²+4+2√2x)(x²+4-2√2x)
=(x²+2√2x+4)(x²-2√2x+4)

◆ 配方。整个分解过程都给你详细写出来了,希望能帮到你。祝学祺!

收起

X四次方+16
=(x⁴+8x²+16)-8x²
=(x²+4)²-(2√2x)²
=(x²+2√2x+4)(x²-2√2x+4)
不懂的还可以追问!满意请及时采纳! O(∩_∩)O

你确定这题没错?

X^4+16
=x^4+8x²+16-8x²
=(x²+4)²-8x²
=(x²+2√2x+4)(x²-2√2x+4)