a^2-3a-1=0,则代数式a^3-10=?

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a^2-3a-1=0,则代数式a^3-10=?
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a^2-3a-1=0,则代数式a^3-10=?
a^2-3a-1=0,则代数式a^3-10=?

a^2-3a-1=0,则代数式a^3-10=?
a^2-3a-1=0,
a²-3a=1
则代数式
a^3-10
=a³-3a²+3a²-10
=a(a²-3a)+3a²-10
=a×1+3a²-10
=a+3a²-10
=3a²+a-10
=3a²-9a+10a-10
=3(a²-3a)+10a-10
=3+10a-10
=10a-7
题目你掉字了吧,不然怎么不能算到底啊,还是题目有问题,要改动的话

a^2-3a-1=0
a=9/2加减根号13/2
a^3-10=10a-7=38+5根号13或38-5根号13