＃define N 3 #define Y(n) ((N+1)*n) 执行Y(5+1)语句后,结果是21不是24,这是怎么回＃define N 3#define Y(n)((N+1)*n)执行Y(5+1)语句后,结果是21不是24,这是怎么回事?

#define #define s(x) 3 #define S(x) 3 #define N 3 #define Y(n) ((N=1)*n) 则表达式2*（N+Y（5+1))的值是#define N 3 #define Y(n) ((N+1)*n) 则表达式2*（N+Y（5+1))的值是 #define PWM_PCR_PWMENAn(n) ((uint32_t)(((n&0x7) #define N 3 #define Y(n) ( (N+1)*n) 则执行语句:z=2 * (N+Y(5+1));后,z的值为 #define N 2 #define M N+1 #define K M+1*M/2#define N 2#define M N+1#define K M+1*M/2main(){int i;for(i=1;i #define getbit( b,n) (((b) & (1L 下面的程序结果是什么?怎么算?急求答案# include # define M 3# define N M+1# define NN N*N/2void main(){ printf(%d ,NN); printf(%d ,5*NN);} define是什么意思 ＃define N 3 #define Y(n) ((N+1)*n) 执行Y(5+1)语句后,结果是21不是24,这是怎么回＃define N 3#define Y(n)((N+1)*n)执行Y(5+1)语句后,结果是21不是24,这是怎么回事? 下列程序运行结果为：#define P 3 #define S(a) P*a*a main() {int ar; ar=S(3+5); printf( %d,ar); } #define P 3 #define S(a) P*a*a main() {int ar; ar=s(3+5) printf( %d,ar) } 这个答案是29,不懂. C语言中 #define N 30 #define IFADOB(A,B) ((A)&&(B,0)) #define 后面的意思// macros for accessing triangle corners#define TIN_TRIANGLE(i) (i/3)#define TIN_CORNER(i) (i%3)#define TIN_INDEX(t,c) (t*3+c)#define TIN_NEXT(c) ((c+1)%3)#define TIN_PREV(c) ((c+2)%3) 计算机组成原理习题求解1 Briefly define immediate addressing.2 Briefly define direct addressing.3 Briefly define indirect addressing.4 Briefly define register addressing.5 Briefly define register indirectaddressing.6 Briefly define displace C/C++:#define SIGN(n) (n==0?(n 英语翻译define('UC_CONNECT','mysql');define('UC_DBHOST','localhost');define('UC_DBUSER','root');define('UC_DBPW','sohu');define('UC_DBNAME','****');define('UC_DBCHARSET','gbk');define('UC_DBTABLEPRE','`dz7`.uc_');define('UC_DBCONNECT','0');define