tanx+tany=25,cotx+coty=30.tan(x+y)=?RT

来源：学生作业帮助网 编辑：作业帮 时间：2024/11/15 11:48:22
tanx+tany=25,cotx+coty=30.tan(x+y)=?RT
x)+I̫F:%@@(Q]ikbTORBz; ˂y`` *7MS_$/=llC,`~^b`i h $Ag { Zu~E

tanx+tany=25,cotx+coty=30.tan(x+y)=?RT
tanx+tany=25,cotx+coty=30.tan(x+y)=?
RT

tanx+tany=25,cotx+coty=30.tan(x+y)=?RT
cotx+coty
=1/tanx+1/tany
=(tanx+tany)/(tnaxtany)
即30=25/(tanxtany),所以tanxtnay=5/6
tan(x+y)
=(tanx+tany)/(1-tanxtany)
=25/(1-5/6)
=150

cotx+coty=30,所以tanxtany=5/6,tan(x+y)=150

tanx+tany=25,cotx+coty=30.tan(x+y)=?RT tanx+tany=25 cotx+coty=30,那么tan(x+y)=? 求证.(tanx+tany)/(tanx-tany)=(sinx+siny)/(si求证.(tanx+tany)/(tanx-tany)=(sinx+siny)/(sinx-siny) 高手进tanx+tany/tanx-tany=3/2 求tanx/tany? tanX * cotX=? tanX-COTx=多少 (tanx+cotx)sin2x= (tanx+cotx)sin2x= 求满足方程(tanx)^4+(tany)^4+2(cotx)^2(coty)^2=3+sin^2 (x+y)的所有实数对(x,y) y=tanx*cotx奇偶性 已知tanx=3tany(0 设tanx=3tany(0 tan(x+y)=tanx+tany吗 已知tanx=3tany(0 证明 (tanX+tanY)/(tanX-tanY)=(sin(X+Y))/(sin(X-Y))thanks 求证tanx+tany/tanx-tany=sin(x+y）/sin(x-y) （tanx+cotx）sinx2=?A cotx Bsinx Ccosx Dtanx 若a=(tanx)^cotx,b=(cotx)^tanx,c=(tanx)^cosx(0