作业帮计算：cosπ/15×cos2π/15×cos4π/15×cos8π/15
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/15 16:50:08
x){nu_|At 4A0-L"}rِm im(CN}$@.4C}#1
(lAC3\!o("Q Ri_\gU0@凖c.
P:
计算：cosπ/15×cos2π/15×cos4π/15×cos8π/15
计算：cosπ/15×cos2π/15×cos4π/15×cos8π/15
计算：cosπ/15×cos2π/15×cos4π/15×cos8π/15
cosπ/15×cos2π/15×cos4π/15×cos8π/15
=（sinπ/15×cosπ/15×cos2π/15×cos4π/15×cos8π/15）/（sinπ/15）
=（1/2sin2π/15×cos2π/15×cos4π/15×cos8π/15）/（sinπ/15）
=（1/4sin4π/15×cos4π/15×cos8π/15）/（sinπ/15）
=（1/8sin8π/15×cos8π/15）/（sinπ/15）
=（1/16sin16π/15）/sin(16π/15-π）
=（1/16sin16π/15）/（-sin16π/15）
=-1/16
乘sin§/15
计算：cosπ/15×cos2π/15×cos4π/15×cos8π/15
如何计算cos2π/3,
求COSπ/5*COS2π/5
cosπ/5×cos2π/5=
COSπ/5乘以COS2π/5
cosπ/5×cos2π/5
cosπ/5cos2π/5
cosπ/5cos2π/5=?
cosπ/5 - cos2π/5 怎样变成 cosπ/5 + cos2π/5rt
分别计算：cosπ/3,cosπ/5cos2π/5,cosπ/7cos2π/7cos3π/7根据上述结果猜想一个一般的结论,并给予证明
化简cos2α+cos2(π/3+α)+cos2(π/3-α)化简cos²α+cos²（π/3+α）+cos²（π/3-α）
sinπ.cosπ.sin2π.cos2π分别是多少
cosπ/9*cos2π/9*cos4π/9=?
求值:cosπ/7*cos2π/7*cos3π/7
cosπ/7cos2π/7cos3π/7=?
cosπ/7cos2/7πcos4/7π=
cosπ/9cos2π/9cos23π/9
根号下1减sin(π+2)cos(π+2)化简是多少啊A sin2-cos2 B cos2-sin2 C +-(sin2-cos2) D sin2+cos2