∫（2x－1）cos（x-x＋1）dx求积分?

∫（2x－1）cos（x-x＋1）dx求积分? 求∫cos（3x+1）dx. 求∫[0-->π](1-cos³x ）dx 求∫（cos²x+1）^0.5dx 求不定积分cos（x^2）dx. 求下列不定积分.求详解（1）∫[(cos 2x)／(cos x﹢sin x)]dx; (2) ∫cot²xdx; (3) ∫{(1+2x²)／[x²(1+x²)]}dx; (4) ∫sin²(x／2)dx; (5) ∫[(cos2x)／(sin²xcos²x)]dx; (6) ∫[e^(x-4)]dx;求解 / (cos x + 1 ) dx ∫{（1/cos^2x）-1}dx 求∫(1+cos²x)/(1+cos2x) 求∫(1+cos²x)/(1+cos2x) dx=∫(1+cos²x)/(2cos²x) dx=（这等号这一部不懂.）x/2+(1/2)∫dx/cos²x=x/2+(tanx)/2+C 求∫x/（1-x）dx 求 ∫1/（X+X）dx 求∫1/(sin^4x+cos^4x)dx, 求不定积分∫[1/(sin^2 cos^2(x)]dx 求不定积分∫[1/sin^2cos^2 (x)]dx 求不定积分∫(1+sinx) / cos^2 x dx 求不定积分∫cos(2x+1)dx 求不定积分∫cos(2x-1)dx 求不定积分∫{ x^4 + [1/(3x)]-cos 2x } dx∫{ x^4 + [1/(3x)]-cos 2x } dx