作业帮数学题!求详细过程!帮忙化简!
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/16 09:38:28
xőn0_efPQ<8v $зM+;&@;
uVmU
vϒNy )4l :WU_~ u|=^0ۭ.Ϋj`zmX+~ _zًWr]^^:O Ax2.RdA8ބi1IتM}ENb FDĉx"-xR
X_CC-hwrbFDMK``ZZWԿCE.ZB3{hBZ@ampu
#qb5T9kMl\hϨ5=8&:G{24t?]o1pS
数学题!求详细过程!帮忙化简!
数学题!求详细过程!帮忙化简!
数学题!求详细过程!帮忙化简!
原式=(x-y-x-y)/[(x+y)(x-y)] * (y^2-x^2)/(xy)
=(-2y)/(x^2-y^2)*(y^2-x^2)/(xy)
=2y/(xy)
=2/x
原式=(x-y-x-y)/[(x+y)(x-y)] * (y^2-x^2)/(xy)
=(-2y)/(x^2-y^2)*(y^2-x^2)/(xy)
=2y/(xy)
=2/x
[1/(x+y)-1/(x-y)]*(y/x-x/y)
=[(x-y-x-y)/(x+y)(x-y)]/(y²-x²)/xy
=-2y/(x+y)(x-y)*[-(x+y)(x-y)/xy]
=-2/x
原式=[(x-y)-(x+y)]/[(x+y)(x-y)]×(y²-x²)/xy
=-2y/[(x+y)(x-y)]×(y+x)(y-x)/xy
=2/x
原=(x-y-x-y)/[(x+y)(x-y)] * (y^2-x^2)/(xy)
=(-2y)/(x^2-y^2)*(y^2-x^2)/(xy)
=2y/(xy)
=2/x