log18 9=a,18b=5,求log45 36

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log18 9=a,18b=5,求log45 36
log18 9=a,18b=5,求log45 36

log18 9=a,18b=5,求log45 36
log18 (9 ) = a,
即log18 (18/2) = a,
1- log18 (2) = a,log18 (2) =1-a.
log36( 45)= log18 (45)/ log18 (36)
=[ log18 (9 )+ log18 (5)]/[ log18 (18×2)]
=[ log18 (9 )+ log18 (5)]/ [ log18 (18)+ log18 (2)]
=(a+b)/(1+1-a)= (a+b)/(2-a)

已知log18 9=a,18b=5,求log(30) 36= 已知log18 9=a,log18 5=b,用a,b表示log 36 45. log36 (45)=log18(45)/log18(36) =(log18 5+log18 9)/(log18 18 +log18 2) =(a+b)/(2-a)没理解已知log18 9=a,18^b=5,用a,b表示log(18)45 已知log18 9=a,18^b=5,用a,b表示log(36)5 已知log18 9=a,18^b=5,用a,b表示log(36)5 已知log18 9=a,18^b=5,用a,b表示log(36)45 已知log18 9=a,18^b=5,用a,b表示log(36)45 “log18 9=a,log18 54=b,求18 的2a-b次方” log18 9=a,log18 5=b,求log30 36=?要求写出解题思路, 若log18 9=a ,18 ^b =5,用a,b表示log小36 大45? log18 9=a log18 5=b 用a,b表示log36 45 已知18^a=5,log18 9=b 求log45 9 log18 9=a,18b=5,求log45 36 log18 9=a,18b=5,求log45 36 log18 3=a log18 5=b 求log36 45这么求,要用具体的过程 log18(9)=a log18(5)=b 用含a,b的式子表示 log36(45)为多少? 已知log18^9=a,18^b=5.求log45的值.